Question

If the moment of inertia is 5 kg.m2, and it is spinning at 5.2 revolutions/minute, what is the angular momentum in kg.m2/s?

Answer 1

The angular momentum of an object with a moment of inertia of 5 kg.m2 and a rotational speed of 5.2 revolutions/minute is 2.72 kg.m2/s.

Step-by-step explanation:

To calculate the angular momentum, we use the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω (omega) is the angular velocity. Given the moment of inertia (I) as 5 kg.m2 and the rotational speed as 5.2 revolutions/minute, we first need to convert the speed into radians per second.

There are 2π radians in one revolution, and 60 seconds in one minute, so:

ω = 5.2 rev/min × (2π rad/rev) / (60 s/min) = 0.544 rad/s

Now, using the formula for angular momentum:

L = Iω = 5 kg.m2 × 0.544 rad/s = 2.72 kg.m2/s

The angular momentum of the object is therefore 2.72 kg.m2/s.