Final answer:
To raise the temperature of 50.0 g of methanol from 20.0 °C to 60.0 °C, it would take 5020 joules of heat energy.
Step-by-step explanation:
To calculate the amount of heat energy required to raise the temperature of methanol, we can use the equation:
q = m * c * ΔT
where q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Given:
Specific heat of methanol (c) = 2.51 J/g·°C
Mass of methanol (m) = 50.0 g
Change in temperature (ΔT) = (60.0 °C - 20.0 °C) = 40.0 °C
Substituting these values into the equation, we have:
q = 50.0 g * 2.51 J/g·°C * 40.0 °C
Calculating this gives us:
q = 50.0 g * 2.51 J/g·°C * 40.0 °C = 5020 J
Therefore, it would take 5020 joules of heat energy to raise the temperature of 50 grams of methanol from 20.0 °C to 60.0 °C.