Question

10.11 ml of 0.3545 M NaOH was required to neutralize 25.00 ml of HCl with unknown molarity. How many moles of NaOH were used?

Answer 1

To find the moles of NaOH used, multiply the given volume in liters by the molarity, which results in 0.00358 moles of NaOH used for neutralization.

Step-by-step explanation:

To calculate the number of moles of NaOH used in the titration, we use the given concentration and volume. First, convert volume from milliliters to liters:

VNaOH = 10.11 mL = 0.01011 L

Next, use the molarity and volume to find the moles of NaOH:

nNaOH = MNaOH × VNaOH

nNaOH = 0.3545 M × 0.01011 L

nNaOH = 0.00358 moles

Therefore, 0.00358 moles of NaOH were used to neutralize the HCl.