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Given h(x) = 4x⁴ - 2x³ + 6x² - 3x + 1, find h'(x) (the derivative of h with respect to x).

User Axelarge
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Final answer:

The derivative of h(x) = 4x⁴ - 2x³ + 6x² - 3x + 1 is h'(x) = 16x³ - 6x² + 12x - 3.

Step-by-step explanation:

The given function is h(x) = 4x⁴ - 2x³ + 6x² - 3x + 1. To find the derivative of h(x), we differentiate each term with respect to x. Using the power rule, the derivative of xⁿ is nxⁿ⁻¹, where n is a constant.

Therefore, the derivative of h(x) = 4x⁴ - 2x³ + 6x² - 3x + 1 is:

h'(x) = 16x³ - 6x² + 12x - 3.

User Rahmouni Rabii
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