Question

A uniform electric field between two metal plates points downwards and has a strength of 4.6 x 10^4 N/C. What force would a 3.2 x 10^-5 C charge experience if it were placed in that field?

Answer 1

The force experienced by a charge of 3.2 x 10^-5 C in an electric field of 4.6 x 10^4 N/C is 1.472 x 10^-1 N, directed downwards, following the equation F = qE.

Step-by-step explanation:

The question asks about the force experienced by a charge in an electric field. To find the force (F) on a charge (q) in an electric field (E), you can use the formula F = qE. Given the electric field strength is 4.6 x 104 N/C and the charge is 3.2 x 10-5 C, the force can be calculated as follows:

F = (3.2 x 10-5 C) x (4.6 x 104 N/C) = 1.472 x 10-1 N

Therefore, the charge would experience a force of 1.472 x 10-1 Newtons in the downward direction of the electric field.