Final answer:
By adding up the points from 3-pointers (9 points), regular baskets (10 points), and free throws (3 points), David Lee Roth scored a total of 22 points in his basketball game.
Step-by-step explanation:
To calculate the total number of points scored by David Lee Roth, we have to consider the value of each type of basketball shot he made. Three-pointers are worth 3 points each, regular baskets are worth 2 points each, and free throws are worth 1 point each.
Let's calculate his total points:
- 3 3-pointers: 3 × 3 points = 9 points
- 5 regular baskets: 5 × 2 points = 10 points
- 3 free throws: 3 × 1 point = 3 points
Now, let's add them all up:
9 points (from 3-pointers) + 10 points (from regular baskets) + 3 points (from free throws) = 22 points total.
Therefore, David scored 22 points in total during his basketball game.