Final answer:
The momentum of the box at the end of the three-second interval when a force of 10 N is applied is 30 kg·m/s, calculated using the formula for impulse.
Step-by-step explanation:
If a force of 10 N acts on a box initially at rest for three seconds, the momentum of the box at the end of the three-second interval can be determined using the concept of impulse. Impulse is the product of the force applied and the time interval for which it acts. The equation for impulse (J) is J = F × t, where F is the force and t is the time. To obtain the momentum (p) after the application of the force, we use the fact that impulse is also equal to the change in momentum (∆p). Since the box is initially at rest, its initial momentum is zero. Therefore, the final momentum of the box is simply equal to the impulse.
The calculation is as follows:
- Force (F) = 10 N
- Time (t) = 3 s
- Impulse (J) = F × t = 10 N × 3 s = 30 Ns
- Momentum (p) after 3 seconds = Impulse (J) = 30 kg·m/s
Therefore, the momentum of the box at the end of the three seconds is 30 kg·m/s.