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One integer is 3 more than twice another integer. The sum of these integers is greater than 24. Find the smallest values for these integers.

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Final answer:

To find the smallest values for the integers, we can set up equations based on the given information and solve for the values of the integers.

Step-by-step explanation:

To find the smallest values for the integers, let's assume one integer is represented by x and the other by y.

We are given that one integer is 3 more than twice the other. So we can set up the equation x = 2y + 3.

The sum of the integers is greater than 24, so x + y > 24.

Now, we need to find the smallest values that satisfy both equations. Let's start by substituting the value of x from the first equation into the second equation:

2y + 3 + y > 24

Combining like terms, we get 3y + 3 > 24.

Subtracting 3 from both sides, we have 3y > 21.

Finally, dividing both sides by 3, we find y > 7.

Since y must be an integer, the smallest possible value for y is 8.

Substituting this value back into the first equation, we have x = 2(8) + 3, which gives x = 19.

Therefore, the smallest values for the integers are y = 8 and x = 19.

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