Question

Four resistors are in series with a 10 V source. The voltage drops across three of the resistors are 1.4 V, 2.2 V, and 3.5 V. How much voltage is dropped across the fifth resistor?

Answer 1

In a series circuit with a 10 V source, the voltage drop across the fourth resistor is 2.9 V after accounting for the voltage drops of the other three resistors.

Step-by-step explanation:

The subject of this question is Physics, specifically related to electric circuits and the concept of series resistors and voltage drops. You have provided information about voltage drops across three resistors, which total 1.4 V + 2.2 V + 3.5 V = 7.1 V. Since the resistors are in series with a 10 V source, the voltage drop across the fourth resistor (not fifth, as there is a typo in the original question) can be found by subtracting the total voltage drop of the three resistors from the total voltage supplied by the source. Therefore, the voltage across the fourth resistor is 10 V - 7.1 V = 2.9 V.