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Two Ships leave port at the same time. Ship X is heading due north andShip y is heading due east. Thirteen hours later they are 650 milesapart. If Ship X had traveled 520 miles from the port, how many mileshad Ship y traveled?

User Cal
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1 Answer

22 votes
22 votes

390

Step-by-step explanation

Step 1

then, we have a rigth triangle

we can use Pitagoras theorem to find the missing distance

Let

adjancent side= 520

opposite side= x

hypotenuse = 650

Step 2

apply the P.T.


\begin{gathered} \text{adjside}^2+opposside^2=hypotenuse^2 \\ 520^2+x^2=650^2 \\ solve\text{ for x} \\ x^2=650^2-520^2 \\ x=\sqrt[]{650^2-520^2} \\ x=\sqrt[]{152100} \\ x=390 \\ \end{gathered}

Hence, ship y has traveled 390

Two Ships leave port at the same time. Ship X is heading due north andShip y is heading-example-1
User Hmmm
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