Final answer:
To find the percentage of the total voltage across a 22 Ω resistor in a series circuit with a total resistance of 470 Ω, use the ratio of the resistor's resistance to the total resistance, yielding 4.68% of the total voltage across this resistor.
Step-by-step explanation:
To determine what percentage of the total voltage appears across a 22 Ω resistor in a series circuit with a total resistance of 470 Ω, you can use Ohm's Law, which states that V = I × R (voltage equals current times resistance). In a series circuit, the current passing through all resistors is the same. Therefore, the voltage drop across a resistor in a series circuit is proportional to its resistance compared to the total resistance of the circuit. Using this principle, the percentage of the total voltage across the 22 Ω resistor is calculated by the formula percentage = (resistor value / total resistance) × 100%.
Let's apply this formula:
percentage = (22 Ω / 470 Ω) × 100%
= (0.04680) × 100%
= 4.68%
So, 4.68% of the total voltage appears across the 22 Ω resistor in the series circuit.