112k views
2 votes
Which shows the linear equation y² = (1/6)(x - 12) written in standard form?

1) y = (1/6)x - 2
2) y = (1/6)x + 2
3) y = (1/6)x - 12
4) y = (1/6)x + 12

User Jameela
by
8.6k points

1 Answer

3 votes

Final answer:

The linear equation y² = (1/6)(x - 12) can be written in standard form as y = (1/6)x - 2.

Step-by-step explanation:

The linear equation y² = (1/6)(x - 12) can be written in standard form as y = (1/6)x - 2.

Here's how to convert it:

  1. Start with the given equation: y² = (1/6)(x - 12)
  2. Take the square root of both sides to isolate y: y = ±√((1/6)(x - 12))
  3. Since y cannot be negative, we can ignore the negative square root
  4. Simplify the expression inside the square root: y = √((x - 12)/6)
  5. Multiply both the numerator and denominator by 6 to clear the fraction: y = (1/6)x - 2

User Boris Burkov
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories