Question

Natasha and her two dogs were walking on a perfectly straight road when her two dogs ran away from her in opposite directions. her beagle is now 25/4 meters directly to her right, and her labrador is 51/20 meters directly to her left.

Answer 1

The dog's net displacement vector is (0, 1) blocks. The magnitude of the net displacement is 1 block. The direction of the net displacement is north.

Step-by-step explanation:

Physics

The net displacement vector of the dog can be found by adding the individual displacement vectors together. The dog ran three blocks east (positive x-axis), two blocks north (positive y-axis), one block east, one block north, and two blocks west. The displacement vectors in the x-axis cancel out and the displacement vectors in the y-axis add up to give a net displacement of (0, 1) blocks.

The magnitude of the net displacement vector can be calculated using the Pythagorean theorem: magnitude = sqrt((0)^2 + (1)^2) = 1 block.

The direction of the net displacement vector can be found using the inverse tangent function: direction = arctan(1/0) = 90 degrees or north.