Final answer:
To prepare 1 liter of 0.1 M KOH, dissolve 5.6 grams of KOH in water. The normality of this solution is also 0.1 N, as the valence of KOH is 1.
Step-by-step explanation:
To prepare 1 liter of 0.1 M potassium hydroxide (KOH), you need to dissolve a specific amount of KOH in water. The molecular weight of KOH is 56 g/mol. Since molarity (M) is defined as moles of solute per liter of solution, you can calculate the amount of KOH needed using the formula:
M = (mass (g) / molecular weight (g/mol)) / volume (L)
For a 0.1 M solution:
0.1 M = (mass / 56 g/mol) / 1 L
Therefore, mass = 0.1 M \u00d7 56 g/mol \u00d7 1 L = 5.6 grams
The correct answer is a) Dissolve 5.6 grams of KOH in 1 liter of water.
Since the valence of KOH is 1, the normality (N) of the solution is the same as the molarity. Thus, the solution also has a normality of 0.1 N.