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Moony's snack factory produces 16 ounce bags of chips. After a day of production, a sample of bags was tested to find that the average weight of a bag was 15.2 ounces with a standard deviation of 0.53 ounces. Find the highest value of a bag of chips such that all weights less than this represent the lower 30.

User Melody
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Final answer:

To find the highest value of a bag of chips representing the lower 30 percent of weights, we use the z-score corresponding to a cumulative probability of 0.30 and convert it to the original scale using the mean (15.2 ounces) and standard deviation (0.53 ounces).

Step-by-step explanation:

The highest value of a bag of chips that represents the lower 30 percent of weights can be determined using the concept of a z-score in statistics. A z-score is the number of standard deviations an observation is away from the mean. To find the value representing the lower 30 percent, we can look up the z-score that corresponds to a cumulative probability of 0.30 in the standard normal distribution table. Once the z-score is identified, we use the formula for converting a z-score to the original scale:

Z = (X - μ) / σ

where Z is the z-score, μ (mu) is the mean, σ (sigma) is the standard deviation, and X is the value on the original scale. We rearrange this formula to solve for X:

X = Z * σ + μ

If the standard normal distribution table indicates that the z-score for the lower 30 percent is, for example, -0.52 (hypothetical value), we would substitute this value along with the given mean (15.2 ounces) and standard deviation (0.53 ounces) into the equation:

X = (-0.52) * (0.53) + 15.2

After performing the calculations, we would obtain the highest value for a bag of chips which represents the lower 30 percent.

User Blabdouze
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