Final answer:
The metal sample absorbed 2250 J when its temperature was raised from 25°C to 100°C; the calculation used the formula: № = m×c×ΔT. The answer options provided in the question contain a typo, as none exactly match the calculated value.
Step-by-step explanation:
To calculate the heat (№) absorbed by the metal sample, we can use the formula № = mcΔT, where № is the heat absorbed, m is the mass of the metal, c is the specific heat capacity of the metal, and ΔT is the change in temperature. Given that the mass (m) of the metal is 20.0 g, the specific heat capacity (c) is 1.50 J/(g°C), and the change in temperature (ΔT) is from 25 °C to 100 °C, a difference of 75°C.
The calculation would be as follows:
№ = m × c × ΔT
№ = 20.0 g × 1.50 J/(g°C) × (100°C - 25°C)
№ = 20.0 g × 1.50 J/(g°C) × 75°C
№ = 20.0 g × 1.50 J/(g°C) × 75°C
№ = 20.0 g × 112.5 J/°C
№ = 2250 J
Therefore, option (c) 2250 J is the correct amount of heat absorbed by the metal sample. Note that none of the answer options given (a) 250 J, (b) 750 J, (c) 2000 J, (d) 5000 J match the calculated value, which suggests a possible typo in the question. The nearest given option is (c) 2000 J, but it is not the exact value.