Final answer:
To find the concentration of AgNO3, convert the mass of AgI to moles using its molar mass, deduce the moles of AgNO3, and divide by the volume of the AgNO3 solution. The resulting concentration is 0.100 M which correlates with the hint provided.
Step-by-step explanation:
To calculate the concentration of AgNO3 from the reaction with HI gas producing AgI, we need to use the molar mass of AgI and the volume of the AgNO3 solution. Given that 0.235 g of AgI is formed from 10.0 mL of AgNO3 solution, we need to find the number of moles of AgI using its molar mass (234.77 g/mol). After calculating the moles of AgI, we can deduce the moles of AgNO3, since the reaction of AgNO3 with HI occurs in a 1:1 molar ratio to produce AgI. Lastly, we find the concentration of AgNO3 by dividing the number of moles of AgNO3 by the volume of the solution in liters.
Here is the step-by-step calculation:
- Convert the mass of AgI to moles:
(0.235 g AgI) / (234.77 g/mol) = 0.00100 mol AgI - Since the molar ratio of AgNO3 to AgI is 1:1, moles of AgNO3 = moles of AgI = 0.00100 mol
- Convert 10.0 mL of AgNO3 solution to liters: 10.0 mL = 0.0100 L
- Calculate the concentration of AgNO3:
(0.00100 mol) / (0.0100 L) = 0.100 M
This confirms the given hint that the concentration of the AgNO3 solution is approximately 0.10 M.