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Suppose 83g of KCl react, and 22g of potassium are produced in the reaction above. Calculate how much chlorine is produced.

a) 61g
b) 105g
c) 83g
d) 44g

User Kaesha
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1 Answer

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Final answer:

The mass of chlorine produced when 83g of KCl reacts, and 22g of potassium are produced, is 61g, which is option a).

Step-by-step explanation:

If 83g of KCl reacts and 22g of potassium (K) are produced, we can determine the mass of chlorine (Cl) produced using the law of conservation of mass. Since potassium chloride (KCl) decomposes into potassium and chlorine, the mass of chlorine produced can be calculated by subtracting the mass of potassium from the initial mass of potassium chloride. Thus, the mass of chlorine produced would be:

Mass of KCl (initial) - Mass of K (produced) = Mass of Cl (produced)

83g (KCl) - 22g (K) = 61g (Cl)

Therefore, the correct answer is a) 61g. This is consistent with the principle that the mass of products in a chemical reaction equals the mass of reactants, as per the law of conservation of mass.

User Pronskiy
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