Final answer:
To determine the hypersonic plane's travel distance per second, you convert 5040 miles per hour to feet per second by multiplying by 5280 (feet in a mile) and dividing by 3600 (seconds in an hour). The calculated answer is 7392 feet per second, which is not listed, but option A, 7,366.08 feet per second, is the closest.
Step-by-step explanation:
To find out how many feet per second a hypersonic plane traveling at 5040 miles per hour would be able to travel, we need to perform unit conversions from miles per hour to feet per second. There are 5280 feet in a mile and 3600 seconds in an hour, so:
5040 miles/hour × 5280 feet/mile = 26,611,200 feet/hour
26,611,200 feet/hour ÷ 3600 seconds/hour = 7392 feet/second
The closest answer to this calculation given in the options is:
B. 8,832.00 feet per second
This might be an error as none of the provided options are exactly correct. The calculated answer of 7392 feet per second is not available in the options so if we have to pick one, A. 7,366.08 feet per second is closest to our calculation.