Question

Each capacitor has c = 4.80 mf and vab = 30.0 v. Calculate:

(a) the charge on each capacitor;
(b) the potential difference across each capacitor?

Answer 1

The charge on each capacitor is 144 µC, and the potential difference across each capacitor is 30.0 V.

Step-by-step explanation:

(a) The charge on each capacitor:

To find the charge on each capacitor, we can use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor.

For the given capacitor with capacitance 4.80 µF and potential difference 30.0 V, the charge can be calculated as:

Q = (4.80 µF)(30.0 V) = 144 µC

Therefore, the charge on each capacitor is 144 µC.

(b) The potential difference across each capacitor:

In an ideal series circuit, the potential difference across each component is the same as the total potential difference. Therefore, the potential difference across each capacitor is 30.0 V.