Question

A vehicle, starting from rest, accelerates at 2.87m/s² on a circular track with a 285m diameter. What is the magnitude of the centripetal acceleration of the vehicle?

1) 2.87 m/s²
2) 5.74 m/s²
3) 11.48 m/s²
4) 22.96 m/s²

Answer 1

The magnitude of the centripetal acceleration of the vehicle is 5.74 m/s².

Step-by-step explanation:

The magnitude of the centripetal acceleration of the vehicle can be calculated using the formula a = v²/r, where v is the velocity and r is the radius of the circular track. The radius of the track is half of its diameter, so it is 285m/2 = 142.5m. Since the vehicle starts from rest, its initial velocity is 0 m/s. Plugging these values into the formula, we get a = (2.87m/s²)²/(142.5m) = 0.0574 m/s². Therefore, the correct answer is option 2) 5.74 m/s².