Question

Determine the number of moles of the excess reactant that remains after 0.600 mol of k2cro4 reacts with 0.500 mol of sulfur dioxide in the presence of an excess of hydrochloric acid according to the above reaction?

Answer 1

To determine the number of moles of the excess reactant that remains, subtract the moles of the limiting reactant that reacted from the initial moles of the excess reactant.

Step-by-step explanation:

To determine the number of moles of the excess reactant that remains, we first need to identify the limiting reactant in the reaction. From the given information, we know that 0.600 mol of K2CrO4 reacts with 0.500 mol of sulfur dioxide in the presence of an excess of hydrochloric acid. We also know that the stoichiometric coefficient of K2CrO4 is 1, meaning that 1 mole of K2CrO4 reacts with 1 mole of sulfur dioxide. Therefore, the limiting reactant is K2CrO4, and the excess reactant is sulfur dioxide.

To find the number of moles of the excess reactant that remains, we need to calculate the moles of sulfur dioxide that reacted. Since the stoichiometric coefficient of K2CrO4 is 1, this means that 1 mole of K2CrO4 reacted. Therefore, 0.600 mol - 1 mol = 0.600 mol of K2CrO4 remains.