188k views
2 votes
A soccer ball is dropped from a height of 3.35 m above the ground. After it bounces, it only reaches a height of 2.47 m above the ground. The soccer ball has a mass of 0.1095 kg. What is the gravitational potential energy of the soccer ball when it is at a height of 3.35 m above the ground?

1 Answer

3 votes

Final answer:

The gravitational potential energy of the soccer ball at a height of 3.35 m above the ground is approximately 3.62 joules, calculated using the formula PE = mgh with the mass of the ball, the acceleration due to gravity, and the given height.

Step-by-step explanation:

The gravitational potential energy of an object is calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.81 m/s² on Earth), and h is the height of the object above the reference point.

In this case, to find the gravitational potential energy of the soccer ball at a height of 3.35 m, we plug in the given values into the formula:

PE = 0.1095 kg × 9.81 m/s² × 3.35 m

PE = 3.6198725 J

Therefore, the gravitational potential energy of the soccer ball when it is at a height of 3.35 m above the ground is approximately 3.62 joules.

User Enfinet
by
8.3k points