Question

Find the equation of the axis of symmetry of the parabola represented by the equation:

y = 2x^2 + 32x + 136
a) x = -16
b) x = -8
c) x = -32
d) x = -4

Answer 1

The equation of the axis of symmetry for the given parabola y = 2x^2 + 32x + 136 is x = -8.

Step-by-step explanation:

The equation of the axis of symmetry of a parabola in the form y = ax^2 + bx + c is given by x = -b/2a.

In this case, the equation is y = 2x^2 + 32x + 136, so a = 2 and b = 32. Plugging these values into the formula, we get x = -32/(2 * 2) = -8.

Therefore, the equation of the axis of symmetry for the given parabola is x = -8.