Question

An object has a speed of 2.00 m/s. Three seconds later, it is going 8.00 m/s. What average acceleration did it experience?

a) 2.00 m/s^2
b) 2.33 m/s^2
c) 2.67 m/s^2
d) 3.00 m/s^2

Answer 1

The average acceleration of an object whose speed changes from 2.00 m/s to 8.00 m/s over 3 seconds is calculated as 2.00 m/s².

Step-by-step explanation:

The question involves finding the average acceleration of an object whose speed changes from 2.00 m/s to 8.00 m/s in a time interval of 3 seconds. Acceleration can be calculated using the formula:

a = ∆v / ∆t

where ∆v is the change in velocity, and ∆t is the change in time. The change in velocity (∆v) is 8.00 m/s - 2.00 m/s = 6.00 m/s. Using the given time of 3 seconds, the average acceleration is calculated as follows:

a = 6.00 m/s / 3 s = 2.00 m/s²

Therefore, the average acceleration the object experienced is 2.00 m/s², which corresponds to option (a).