Question

If you had a balloon that had a volume of 1463 ml and was at a temperature of 80°C, what temperature in °C would you have to change it to if you wanted the balloon to have a volume of 1.13 liters?

a) 40°C
b) 60°C
c) 100°C
d) 120°C

Answer 1

To change a balloon's volume from 1.463 liters at 80°C to 1.13 liters, you would need to adjust the temperature to 0°C. This answer is calculated by using Charles's Law, which relates the volume of a gas to its temperature when pressure is held constant.

Step-by-step explanation:

If a balloon has a volume of 1463 ml (which is equivalent to 1.463 liters) at a temperature of 80°C, and we want to change its volume to 1.13 liters, we need to find the new temperature using Charles's Law. This law states that the volume of a gas is directly proportional to its temperature (in Kelvin), providing the pressure remains constant. Therefore, we can set up the following proportion:

(V1 / T1) = (V2 / T2), where V1 is the initial volume, T1 is the initial temperature in Kelvin, V2 is the final volume, and T2 is the final temperature in Kelvin.

First, convert the initial and final volumes to liters if they're not already, and convert the Celsius temperatures to Kelvin by adding 273.15.

Initial conditions: V1 = 1.463 L, T1 = 80°C = 353.15 K
Final condition: V2 = 1.13 L

T2 = (V2 * T1) / V1
T2 = (1.13 L * 353.15 K) / 1.463 L
T2 = 273.15 K
T2 = 0°C

Therefore, you would need to change the temperature of the balloon to 0°C to achieve a volume of 1.13 liters.