Final answer:
The average atomic mass of element X, considering the natural abundances and isotopic masses of its isotopes ^40X and ^42X, is calculated to be ~40.46 amu, which after rounding, matches most closely with Option B: 40.00 amu.
Step-by-step explanation:
To calculate the average atomic mass of an element with multiple isotopes, we use the natural abundances and isotopic masses of each isotope. The average atomic mass is a weighted average, meaning that each isotope contributes to the atomic mass in proportion to its natural abundance.
For the element X, which has two isotopes ^40X and ^42X:
- The contribution of ^40X to the average atomic mass is (0.75 × 39.96 amu) = 29.97 amu.
- The contribution of ^42X to the average atomic mass is (0.25 × 41.96 amu) = 10.49 amu.
Adding these together:
29.97 amu + 10.49 amu = 40.46 amu
This value doesn't exactly match any of the provided multiple-choice options, indicating a possible discrepancy. However, if we consider standard rounding conventions, the closest answer choice to 40.46 amu would be Option B: 40.00 amu.