160k views
5 votes
The curve y = 3x^2 - 2x + c - 1 cuts the x-axis at two points. Find the range values of c.

a. c < -1
b. c ≤ -1
c. c > -1
d. c ≥ -1

1 Answer

7 votes

Final answer:

The range of values for c that ensures the curve y = 3x^2 - 2x + c - 1 intersects the x-axis at two points is c > -1, as this results in a discriminant greater than zero which indicates two distinct real roots.

Step-by-step explanation:

To determine the range of values for c for which the curve y = 3x^2 - 2x + c - 1 cuts the x-axis at two points, we need to consider the discriminant of the quadratic equation. For a quadratic equation ax^2 + bx + c = 0, the discriminant is given by b^2 - 4ac. If the discriminant is greater than 0, the equation has two distinct real roots, which means the curve intersects the x-axis at two points.

In the given equation, a = 3, b = -2, and c is the constant we are trying to find. Substituting a and b into the discriminant formula gives us (-2)^2 - 4(3)(c - 1). For the curve to cut the x-axis at two points, this discriminant must be greater than 0, which leads us to the inequality 4 - 12(c - 1) > 0. Solving for c gives us c > -1.

So, the correct range of values for c such that the curve intersects the x-axis at two points is c > -1.

User Oscarm
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories