Question

A land-speed car can decelerate at 9.8 m/s^2. How long does it take the car to come to a stop from a run of 245.8 m/s?

a) 25 seconds

b) 20 seconds

c) 15 seconds

d) 10 seconds

Answer 1

To calculate the time for a car to decelerate from 245.8 m/s to a stop with a deceleration of 9.8 m/s^2, the formula t = v / a is used, giving a time of 25 seconds, which is answer (a).

Step-by-step explanation:

The question asks about the time it takes for a land-speed car to decelerate from a speed of 245.8 m/s to a stop at a deceleration rate of 9.8 m/s2. To find the time, we can use the formula for deceleration:

time (t) = velocity (v) / deceleration (a).

Substituting the given values, we get:

t = 245.8 m/s / 9.8 m/s2

This yields:

t = 25 seconds.

Thus, the correct answer is (a) 25 seconds.