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The perimeter of a rectangle with a length of (2y + 6) inches and a width of (y - 4) inches is 52 inches. Find the actual length and width of the rectangle in inches.

a) Length = 10 inches, Width = 8 inches
b) Length = 14 inches, Width = 12 inches
c) Length = 16 inches, Width = 8 inches
d) Length = 18 inches, Width = 10 inches

1 Answer

7 votes

Final answer:

To find the dimensions of the rectangle, an equation is set up using the perimeter formula and the expressions for length and width are solved for y. Substituting y back into the length and width expressions should give the dimensions of the rectangle; however, the options provided don't match the calculated results.

Step-by-step explanation:

The question asks us to find the actual dimensions of a rectangle with a given perimeter and expressions for its length and width. First, we need to form an equation using the formula for the perimeter of the rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.

Given:
Length = (2y + 6) inches
Width = (y - 4) inches
Perimeter = 52 inches
We can write the equation:
52 = 2(2y + 6) + 2(y - 4)

Solving for y gives us:
52 = 4y + 12 + 2y - 8
52 = 6y + 4
48 = 6y
y = 8

Now we substitute y back into the expressions for length and width:
Length = 2(8) + 6 = 22 inches
Width = 8 - 4 = 4 inches

From the options provided, none directly reflect the dimensions calculated. This means an error has occurred in the calculation or options provided.

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