Question

How many calories are required to vaporize 60 ml of water at 100°C? How many kilocalories is that?

a) 60 calories, 0.06 kilocalories
b) 100 calories, 0.1 kilocalories
c) 540 calories, 0.54 kilocalories
d) 6000 calories, 6 kilocalories

Answer 1

The correct amount of calories required to vaporize 60 ml of water at 100°C is 32,400 calories, which is equivalent to 32.4 kilocalories. The options provided in the question do not contain this correct answer.

Step-by-step explanation:

To determine how many calories are required to vaporize 60 ml of water at 100°C, one must know the heat of vaporization of water, which is 540 calories per gram. Since 1 milliliter of water has a mass of approximately 1 gram, we can calculate the required heat for 60 ml as follows:

• Heat required = mass x heat of vaporization
• Heat required = 60 g x 540 cal/g
• Heat required = 32,400 calories

To convert calories to kilocalories, one must divide the number of calories by 1,000:

• 32,400 calories / 1,000 = 32.4 kilocalories

Therefore, the correct answer is not listed among the options provided. The actual amount of heat required to vaporize 60 ml of water at 100°C is 32,400 calories or 32.4 kilocalories.