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What is the value of 'a' in the function f(x) = ax^2 + 2ax + a if the average rate of change over the interval [1,4] is 13?

a) 3
b) 4
c) 5
d) 6

1 Answer

2 votes

Final answer:

The average rate of change of the function f(x) = ax^2 + 2ax + a over the interval [1,4] is calculated to be 7a. Setting this equal to 13 gives us a value for 'a' that does not match any of the provided options, suggesting there may be a mistake in the question.

Step-by-step explanation:

To find the value of 'a' in the function f(x) = ax^2 + 2ax + a where the average rate of change over the interval [1,4] is 13, we need to calculate the change in the function values at x=1 and x=4 and then divide by the change in x.

Firstly, find the function values at x = 1 and x = 4:

  • f(1) = a(1)^2 + 2a(1) + a = a + 2a + a = 4a
  • f(4) = a(4)^2 + 2a(4) + a = 16a + 8a + a = 25a

Next, calculate the average rate of change:

Average rate of change = (f(4) - f(1)) / (4 - 1) = (25a - 4a) / 3 = 21a / 3 = 7a

We are given that the average rate of change is 13, so:

7a = 13

Solve for a:

a = 13 / 7

Which simplifies to:

a ≈ 1.857, which is not any of the options provided; therefore, there might have been a calculation mistake or a typo in the options given.

User Yeakub Bin Aziz
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