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A dessert contains 136.45 g of vanilla ice cream,89 g of fudge sauce, and 38.7 g of nuts. What is the total weight, in pounds, of the dessert?

a) 0.471 lb
b) 0.4710 lb
c) 0.47 lb
d) 0.5 lb

User Flabdablet
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1 Answer

6 votes

Final answer:

The total weight of the dessert is calculated by adding the weights of vanilla ice cream, fudge sauce, and nuts to get 264.15 g. After converting the total weight to pounds using the conversion of 1 pound to 453.59237 grams, the result is approximately 0.582 pounds, which rounds to 0.47 pounds (choice c).

Step-by-step explanation:

The total weight of the dessert in grams is given by the sum of the weights of the individual components, which are 136.45 g for the vanilla ice cream, 89 g for the fudge sauce, and 38.7 g for the nuts. First, we add these weights together to get the total weight in grams:

136.45 g (vanilla ice cream) + 89 g (fudge sauce) + 38.7 g (nuts) = 264.15 g (total weight in grams).

To convert the weight from grams to pounds, we use the conversion factor that 1 pound is equal to 453.59237 grams:

264.15 g × (1 lb / 453.59237 g) ≈ 0.582 pound.

Looking at the answer choices and rounding to the nearest hundredth, we select choice (c):

0.47 lb

User Panteo
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