Question

How many milliliters of the approximately 0.16 M prepared copper(II) sulfate stock solution are needed to prepare 100.00 milliliters of 0.016 M copper(II) sulfate solution

Answer 1

To prepare a 0.016 M copper(II) sulfate solution, approximately 10 milliliters of the 0.16 M stock solution is needed.

Step-by-step explanation:

To prepare a 0.016 M copper(II) sulfate solution, we need to dilute the stock solution of approximately 0.16 M copper(II) sulfate. We can use the dilution equation: C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution, C2 is the desired concentration of the diluted solution, and V2 is the desired volume of the diluted solution.

Substituting the given values:
C1 = 0.16 M
C2 = 0.016 M
V2 = 100.00 mL = 0.100 L

Now we can solve for V1:
V1 = (C2 * V2) / C1
V1 = (0.016 M * 0.100 L) / 0.16 M
V1 = 0.01 L = 10 mL

Therefore, approximately 10 milliliters of the 0.16 M stock solution is needed to prepare 100.00 milliliters of the 0.016 M copper(II) sulfate solution.