Final answer:
The gravitational field strength experienced by the object is calculated to be 0.47 m/s² by using the formula P.E. = mgh and rearranging it to solve for the gravitational field strength (g).
Step-by-step explanation:
The question pertains to computing the gravitational field strength experienced by an object using its gravitational potential energy and height above the ground. To calculate the gravitational field strength, we use the formula for gravitational potential energy, which is P.E. = mgh, where P.E. is the potential energy in joules, m is the mass in kilograms, g is the gravitational field strength in meters per second squared, and h is the height in meters.
Given the object's mass (m) is 3 kg, height (h) is 5 m, and gravitational potential energy (P.E.) is 7 J, we can rearrange the formula to solve for g: g = P.E. / (m * h). Substituting in the given values, g = 7 J / (3 kg * 5 m).
Calculating this, the gravitational field strength (g) experienced by the object is 0.47 m/s². This value is notably less than the average Earth's gravitational field strength of approximately 9.81 m/s², indicating that the given potential energy might be in a context with less gravitational effect or the numerical values could be hypothetical for instructional purposes.