Question

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 3.4x10¹⁰ kg, and the force causes its speed to change from 7600 to 4700 m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 2.4x10^?

Answer 1

To find the work done by the force, use the work-energy theorem. The work done is equal to the change in kinetic energy. If the distance over which the asteroid slows down is provided, we can calculate the work done.

Step-by-step explanation:

To find the work done by the force, we need to use the work-energy theorem. The work done by a force is equal to the change in kinetic energy of the object. In this case, the initial kinetic energy of the asteroid is given by Ek1 = 0.5 * mass * velocity1^2, and the final kinetic energy is given by Ek2 = 0.5 * mass * velocity2^2. The work done by the force is then calculated as W = Ek2 - Ek1. Substituting the given values, we have W = 0.5 * mass * (velocity2^2 - velocity1^2). Plugging in the values, we get:

W = 0.5 * (3.4x10^10 kg) * ((4700 m/s)^2 - (7600 m/s)^2) = 6.276x10^14 J

(b) If the asteroid slows down over a distance of 2.4x10^?

Unfortunately, the question seems to be incomplete as there is no information given about the distance over which the asteroid slows down. Please provide the complete information so that we can assist you further.