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An engineer wants a 4000kg helicopter to fly horizontally and increase speed at a rate of 1.9 m/s² despite experiencing a 1100n drag. What is the net force acting on the helicopter?

1) 1100 N
2) 4000 N
3) 7600 N
4) 5100 N

User Ktzhang
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1 Answer

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The net force acting on the helicopter is the difference between the force needed to accelerate it and the drag force, which is 6500 N. The correct option that represents the net force action wasn't listed in the options provided.

To calculate the net force acting on the helicopter, we use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). The helicopter has a mass of 4000 kg and is accelerating at a rate of 1.9 m/s². Therefore, the force required to accelerate the helicopter is:

F = ma = 4000 kg × 1.9 m/s² = 7600 N.

However, we must also account for the drag force acting on the helicopter, which opposes its motion. The drag force is given as 1100 N. Therefore, the net force is the difference between the force required for acceleration and the drag force:

Net Force = 7600 N - 1100 N = 6500 N.

User Alexander Yatsenko
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