Final answer:
To find how fast a person will be moving at 250 meters above the ground, we use the kinematic equation for free fall. Considering negligible air resistance, we can calculate the velocity using the displacement from 1450 meters to 250 meters and the acceleration due to gravity.
Step-by-step explanation:
To calculate how fast a person will be moving at 250 meters above the ground after stepping out of an airplane at 1450 meters, we can use the principles of free fall under the influence of gravity, assuming negligible air resistance. We apply the kinematic equation that relates final velocity, initial velocity, acceleration due to gravity, and displacement: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is 0 if the person is just stepping out), a is acceleration due to gravity (approximately 9.81 m/s^2), and s is the displacement.
Given that the initial height is 1450 meters and the final height is 250 meters, the displacement s is 1450 - 250 = 1200 meters. Plugging the values into the equation: v^2 = 0 + 2 * 9.81 * 1200. Solving for v, we get:
v = sqrt(2 * 9.81 * 1200)
By calculating the square root, we will find the velocity the person would have just before reaching the 250 meters above the ground, which would be the final answer after performing the calculation.