Question

Fe304 reacts with CO according to the equation

Fe3O4(s) + 4CO(g) → 4C02(g) + 3Fe(s)
If 440.8 g CO is reacted with excess Fe304, what mass of CO2 will be produced?
A) 795.6 g
B) 623.2 g
C) 881.6 g
D) 704.8 g

Answer 1

To find the mass of CO required to react with Fe₂O3, we use the stoichiometry of the balanced equation. We convert the mass of Fe₂O3 to moles, use the mole ratio to calculate the moles of CO, and then convert the moles to mass.

Step-by-step explanation:

To determine the mass of CO (carbon monoxide) required to react with 25.13 g of Fe₂O3 (iron(III) oxide), we need to use the stoichiometry of the balanced equation. The balanced equation is: Fe2O3 + 3CO → 2Fe + 3CO₂. From the equation, we can see that 3 moles of CO are required to react with 1 mole of Fe₂O3. Therefore, we need to convert the mass of Fe₂O3 to moles and then use the mole ratio to calculate the mass of CO needed.

First, calculate the moles of Fe₂O3:
Moles of Fe₂O3 = Mass of Fe₂O3 / Molar mass of Fe₂O3

Next, use the mole ratio from the balanced equation to calculate the moles of CO:
Moles of CO = Moles of Fe₂O3 × (3 moles of CO / 1 mole of Fe₂O3)

Finally, convert the moles of CO to mass:
Mass of CO = Moles of CO × Molar mass of CO

Plug in the values and calculate the answer to find the mass of CO required.