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The reaction of sulfur dichloride (SCl2) and sodium fluoride (NaF) may be represented by the following chemical equation.

3 SCl2 + 4 NaF --> S2Cl2 + SF4 + 4 NaCl
Determine the stoichiometric ratio of NaF to SCl2 in this equation. (Enter the stoichiometric ratio from the balanced equation.)

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Final answer:

The stoichiometric ratio of NaF to SCl2 in the reaction 3 SCl2 + 4 NaF → S2Cl2 + SF4 + 4 NaCl is 4:3, meaning 4 moles of NaF react with 3 moles of SCl2.

Step-by-step explanation:

The stoichiometric ratio of NaF to SCl2 in the balanced chemical equation 3 SCl2 + 4 NaF → S2Cl2 + SF4 + 4 NaCl is determined by comparing the coefficients in front of each substance in the equation. Since stoichiometry in chemistry is about the quantitative relationships between the substances in a chemical reaction, it’s important to understand how these numbers relate. The ratio comes from the balanced equation, and it indicates how much of one reactant is required to react with another.

Using the coefficients, the stoichiometric ratio is 4 moles of NaF to 3 moles of SCl2. This means that 4 moles of sodium fluoride (NaF) will react with 3 moles of sulfur dichloride (SCl2) to produce disulfur dichloride (S2Cl2), sulfur tetrafluoride (SF4), and sodium chloride (NaCl).

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