Question

Determine the molarity of each of the following solutions.

a. 0.454 g of H2SO4 in 1.00 L of solution
b. 20.90 g of Al(NO3)3 in 1563 mL of solution
c. 2.70 kg of CuSO4 · 7 H2O in 309 L of solution
d. 0.005707 mol of Cl2 in 10.60 mL of solution"

Answer 1

To determine the molarity of a solution, divide the moles of solute by the volume of the solution in liters. we need to convert the mass of H2SO4 to moles and then divide by the volume in liters: M = (0.454 g H2SO4 / molar mass of H2SO4) / 1.00 L = x mol/L Using the same approach, you can calculate the molarity for cases (b), (c), and (d) as well.

Step-by-step explanation:

To determine the molarity of a solution, we need to know the number of moles of solute and the volume of the solution. Molarity (M) is calculated by dividing the moles of solute by the volume of the solution in liters. For example, in case (a), 0.454 g of H2SO4 in 1.00 L of solution, we need to convert the mass of H2SO4 to moles and then divide by the volume in liters: M = (0.454 g H2SO4 / molar mass of H2SO4) / 1.00 L = x mol/L Using the same approach, you can calculate the molarity for cases (b), (c), and (d) as well.

molarity of a solution, divide the moles of solute by the volume of the solution in liters. we need to convert the mass of H2SO4 to moles and then divide by the volume in liters: M = (0.454 g H2SO4 / molar mass of H2SO4) / 1.00 L = x mol/L Using the same approach, you can calculate the molarity for cases (b), (c), and (d) as well.