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A recent study indicates that 1 out of 4 households do not have internet access. If 17 households are randomly selected then what is the probability that more than 6 will not have internet access? Give your answer to four decimal places.

a. 0.1447
b. 0.8553
c. 0.5447
d. 0.4553

User Hadas
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Final answer:

The probability that more than 6 out of 17 households do not have internet access can be found using a binomial distribution with n=17 and p=0.25. The exact probability requires calculation with statistical software or a calculator capable of binomial functions.

Step-by-step explanation:

The probability question you asked about involves finding the chance that more than 6 out of 17 randomly selected households do not have internet access, given that 1 out of 4 households generally do not. This question can be modeled as a binomial distribution problem where n=17, the number of trials, and p=0.25, the probability of success (a household not having internet access).

To find the probability of more than 6 successes (households without internet), we can calculate the cumulative probability of 0 to 6 households not having internet access and subtract it from 1. However, this requires the use of binomial probability formulas or a calculator with binomial distribution functions. As a tutor, I can guide you on the approach, but you would need a calculator or statistical software to obtain the exact value, which should match one of the multiple-choice options provided in your question based on accurate calculations.

User Canor
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