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Taylor is 48 miles away from Dakota. They are traveling towards each other. If Dakota travels 4 mph faster than Taylor and they meet after 3 hours, how fast was each traveling?

a. Taylor is traveling 12 mph, Dakota is traveling 16 mph
b. Taylor is traveling 14 mph, Dakota is traveling 18 mph
c. Taylor is traveling 10 mph, Dakota is traveling 14 mph
d. Taylor is traveling 16 mph, Dakota is traveling 20 mph

1 Answer

2 votes

Final answer:

Taylor and Dakota meet after 3 hours, with Dakota traveling 4 mph faster. Setting the equation 3x + 3(x + 4) = 48 and solving for x gives Taylor's speed as 6 mph, Dakota's as 10 mph. This does not match the options provided, indicating a possible error in the question or options.

Step-by-step explanation:

The student's question involves determining the speeds at which Taylor and Dakota are traveling if they start 48 miles apart and meet after 3 hours, with Dakota traveling 4 mph faster than Taylor. We can solve this problem by setting up equations based on the relationship between distance, rate (speed), and time.

Let Taylor's speed be x mph. Since Dakota's speed is 4 mph faster, Dakota's speed is x + 4 mph. They meet after 3 hours, so combining their distances traveled gives us the total distance:

Taylor's distance + Dakota's distance = Total distance

3x + 3(x + 4) = 48

Expanding this we get:

3x + 3x + 12 = 48

Combining like terms, we have:

6x + 12 = 48

Subtracting 12 from both sides gives us:

6x = 36

Dividing by 6, we find:

x = 6

Therefore, Taylor's speed is 6 mph, and Dakota's speed is 6 + 4 = 10 mph. However, none of the options provided match our calculation. It seems there may be a mistake in either the question or the options provided. The correct speeds should be recalculated or clarified for an accurate answer.

User Gunay Anach
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