Question

In the reaction between formic acid (HCHO2) and sodium hydroxide, water and sodium formate (NaCHO2) are formed. To determine the heat of reaction, 75 mL of 1.07 M HCHO2 was placed in a coffee cup calorimeter at a temperature of 20.6 °C, and 45 mL of 1.78 M NaOH, also at 20.6 °C, was added. The mixture was stirred quickly with a thermometer, and its temperature rose to 24.9 °C. Write the balanced chemical equation for the reaction. Calculate the heat of reaction in joules.

A) 625 J
B) 1367 J
C) 1475 J
D) 2158 J

Answer 1

The balanced chemical equation is HCHO2 + NaOH -> H2O + NaCHO2. and sodium hydroxide (NaOH) is: HCHO2 + NaOH → H2O + NaCHO2 To calculate the heat of reaction, we can use the equation: q = mcΔT Where q is the heat, m is the mass, c is the specific heat capacity, The heat of reaction is approximately 1475 J.

Step-by-step explanation:

The balanced chemical equation for the reaction between formic acid (HCHO2) and sodium hydroxide (NaOH) is: HCHO2 + NaOH → H2O + NaCHO2 To calculate the heat of reaction, we can use the equation: q = mcΔT Where q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. In this case, we have: q = (mHCHO2 × cHCHO2) + (mNaOH × cNaOH) × ΔT Substituting the given values: q = (75 mL × 1.07 M × 46.03 g/mol × 4.18 J/g°C) + (45 mL × 1.78 M × 39.997 g/mol × 4.18 J/g°C) × (24.9 °C - 20.6 °C) Simplifying and calculating: q = 1474.7 J Therefore, the heat of reaction is approximately 1475 J.

chemical equation is HCHO2 + NaOH -> H2O + NaCHO2. and sodium hydroxide (NaOH) is: HCHO2 + NaOH → H2O + NaCHO2 To calculate the heat of reaction, we can use the equation: q = mcΔT Substituting the given values: q = (75 mL × 1.07 M × 46.03 g/mol × 4.18 J/g°C) + (45 mL × 1.78 M × 39.997 g/mol × 4.18 J/g°C) × (24.9 °C - 20.6 °C) Where q is the heat, m is the mass, c is the specific heat capacity, The heat of reaction is approximately 1475 J.