Question

How do you create an input-output table to represent the function Y = 8 + 6x using 0, 1, 2, and 3 as the domain?

a)

x | 0 | 1 | 2 | 3
Y | 8 | 14 | 20 | 26

b)

x | 0 | 1 | 2 | 3
Y | 8 | 16 | 24 | 32

c)

x | 0 | 1 | 2 | 3
Y | 14 | 20 | 26 | 32

d)

x | 0 | 1 | 2 | 3
Y | 6 | 12 | 18 | 24

Answer 1

a)

Step-by-step explanation:

y = 8 + 6x

x = 0

y = 8 + 6×0 = 8 + 0 = 8

x = 1

y = 8 + 6×1 = 8 + 6 = 14

x = 2

y = 8 + 6×2 = 8 + 12 = 20

x = 3

y = 8 + 6×3 = 8 + 18 = 26

these are exactly the given values in a).

Answer 2

To construct the input-output table for the function Y = 8 + 6x with the domain 0, 1, 2, 3, simply calculate the Y-values for each X-value. The correct table is x | 0 | 1 | 2 | 3 Y | 8 | 14 | 20 | 26, which shows the dependence of y on x.

Step-by-step explanation:

To create an input-output table to represent the function Y = 8 + 6x using 0, 1, 2, and 3 as the domain, you simply substitute these x-values into the function and calculate the corresponding Y-values. For instance, when x is 0, Y would be 8 since 8 + 6(0) is 8. When x is 1, Y would be 14 since 8 + 6(1) is 14, and so on for the other values. The complete input-output table would look like this:

• x | 0 | 1 | 2 | 3
• Y | 8 | 14 | 20 | 26

This corresponds to option (a), which accurately reflects the dependence of y on x for the given domain values.