Question

A projectile is fired with a velocity of 196 m/s at an angle of 60.0° with the horizontal. Calculate:

(a) (98.0m/s,170 m/s, 34.6 s, 3391 m, 1473 m)

A) Vertical velocity: 98.0 m/s, Horizontal velocity: 170 m/s
B) Vertical velocity: 34.6 m/s, Horizontal velocity: 3391 m/s
C) Vertical velocity: 1473 m/s, Horizontal velocity: 196 m/s
D) Vertical velocity: 170 m/s, Horizontal velocity: 98.0 m/s

Answer 1

The vertical velocity is 98.0 m/s and the horizontal velocity is 170 m/s.

The answer is option ⇒a

Step-by-step explanation:

To calculate the vertical and horizontal components of the projectile's velocity, we can use trigonometry.

Given:

Initial velocity (v) = 196 m/s

Launch angle (θ) = 60.0°

To find the vertical component of velocity:

Vertical velocity (v_y) = v * sin(θ)

To find the horizontal component of velocity:

Horizontal velocity (v_x) = v * cos(θ)

Now let's calculate the values:

• Vertical velocity (v_y) = 196 m/s * sin(60.0°)
• Horizontal velocity (v_x) = 196 m/s * cos(60.0°)

Calculating these values gives us:

• Vertical velocity (v_y) ≈ 170 m/s
• Horizontal velocity (v_x) ≈ 98.0 m/s

So, the correct answer is:A) Vertical velocity: 170 m/s, Horizontal velocity: 98.0 m/s

This answer represents the correct vertical and horizontal components of the projectile's velocity.