Final answer:
To find two numbers whose sum is 36 and one is 3 more than twice the other, we can set up a system of equations. However, none of the given answer choices match the solution.
Step-by-step explanation:
To solve this problem, we can set up a system of equations. Let's call the two numbers x and y. We are given that x + y = 36 and that one number is 3 more than twice the other number, so we can write the equation x = 2y + 3.
Substituting this into the first equation, we get 2y + 3 + y = 36. Simplifying this equation gives us 3y + 3 = 36. Subtraction 3 from both sides and then dividing both sides by 3, we find that y = 11.
Now we can substitute the value of y back into one of the equations to find the value of x. Using x = 2y + 3, we get x = 2(11) + 3 = 22 + 3 = 25. Therefore, the two numbers are 11 and 25, which is not one of the given options. None of the answer choices provided in the question match the solution.