Question

What volume of 3.50 M H2SO4 is required to prepare 250.0 mL of 1.25 M H2SO4?

A) 0.071 L
B) 0.179 L
C) 0.286 L
D) 0.357 L

Answer 1

The volume of 3.50 M H2SO4 needed to prepare 250.0 mL of a 1.25 M H2SO4 solution is approximately 0.089 L, or 89.29 mL. Therefore, the correct option is B.

Step-by-step explanation:

To determine the volume of the 3.50 M H2SO4 (concentrated sulfuric acid) required to prepare 250.0 mL of 1.25 M H2SO4(diluted sulfuric acid), you can use the formula for dilution: C1V1 = C2V2, where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the diluted solution, respectively.

Using the formula:

C1V1 = C2V2

3.50 M × V1 = 1.25 M × 250.0 mL

V1 = (1.25 M × 250.0 mL) / 3.50 M

V1 = (312.5 mL) / 3.50

V1 = 89.29 mL

Therefore, the volume of the concentrated H2SO4 required is B) 0.089 L, which is equivalent to 89.29 mL. Please note that none of the available options (A-D) exactly match this result, thus there might be an error in the options provided. The correct answer should be approximately 0.089 L.