Question

If 213 J raises a sample of water 8.2°C, what is the mass of the water? (Refer to the table of constants for water.)

A) 26 g
B) 0.16 g
C) 6.2 g
D) 51 g

Answer 1

The mass of water that would be raised by 8.2°C with an input of 213 J of energy is approximately 6.2 grams, using the specific heat capacity formula and the provided constant for water.

Step-by-step explanation:

The question pertains to the calculation of the mass of water based on the amount of heat energy supplied and the temperature change observed. The specific heat capacity of water is a key factor, which is approximately 4.184 J/g °C. To find the mass of water, we can rearrange the formula for heat capacity Q = mcΔT where Q is the heat in joules, m is the mass in grams, c is the specific heat capacity, and ΔT is the temperature change in degrees Celsius.

Given that 213 J of energy raises the temperature of water by 8.2°C, we can calculate the mass of water using the formula: m = Q / (cΔT). Substituting the given values and using the known specific heat capacity of water:

m = 213 J / (4.184 J/g °C × 8.2°C)

The result is a mass of approximately 6.2 grams, making option C the correct answer.