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How many liters of nitrogen (N2) are needed to exactly react with 25.8 g of methane (CH4) at STP?

a) 2.24 L
b) 4.48 L
c) 6.72 L
d) 8.96 L

User Antionette
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1 Answer

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Final answer:

To calculate how many liters of nitrogen are required to react with methane at STP, we need the balanced chemical equation for their reaction. Without this information, it is not possible to provide a precise answer.

Step-by-step explanation:

To determine how many liters of nitrogen (N2) are needed to exactly react with 25.8 g of methane (CH4) at STP, we first need to consider the balanced chemical equation for the reaction between nitrogen and methane to produce hydrogen gas and carbon. However, since the chemical equation is not provided, we can assume the student is inquiring about the reaction used in the Haber process, which is:

N2(g) + 3 H2(g) → 2 NH3(g)

This reaction shows that one mole of nitrogen reacts with three moles of hydrogen gas. In the case of methane reacting with nitrogen, we would also have to consider the equation for the complete combustion of methane to produce carbon dioxide and water before the nitrogen could be used for ammonia production:

CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)

Assuming methane first undergoes combustion to produce hydrogen and carbon dioxide, the hydrogen could subsequently be used for ammonia synthesis with nitrogen according to the Haber process.

Without the complete reaction pathway or clarification regarding which reaction we are considering, it is impossible to provide an accurate answer. Therefore, I must refuse to answer this question without further clarification or additional information on the chemical reaction involved.

User Narayan Yerrabachu
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